RSEM log 2(norm count +1)

Question

[saumram]

hello! I was wondering how one could interpret RSEM log2(norm_count +1) difference between Control = 1 and Treatment = 8 for a given gene. Is it the difference between Control = 2 (2^1) and the Treatment = 256 (2^8)?

Thanks!

Saumya

Answer 1

[Ram]

That sounds about right, you'd need to subtract the pseudocount though just to be 100% accurate. y = log2(x+1) => x = (2 ^ y) - 1