Remove from a list or replace NaN with a value

Question

[Morteza Hadizadeh]

Hi every one, During microarray meta-analysis, I encounter below error.

# "anals” class is a list.

es_res <- es_meta(anals, by_source = TRUE) Error in quantile.default(x, probs = c(0.25, 0.75)) : missing values and NaN's not allowed if 'na.rm' is FALSE

please guide me, which one is more logical, remove NaN or replace with a value? How to remove or replace NaN with a value? I would be very pleased if you could guide me.

Answer 1

[Jean-Karim Heriche]

Removing NaNs and missing values is an R programming exercise. Replacing missing values is called imputation. There are quite a few articles on methods for doing this with microarray data. See for example:

• Dealing with missing values in large-scale studies: microarray data imputation and beyond
• Missing value imputation for microarray data: a comprehensive comparison study and a web tool