# SAT Math Multiple Choice Question 41: Answer and Explanation

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**Question: 41**

**1.** Let the function f be defined such that f(x) = x^{2} - c, where c is a constant. If f(-2) = 6, what is the value of c ?

- A. -10
- B. -2
- C. 0
- D. 2

**Correct Answer:** B

**Explanation:**

B Start by plugging in what you know into the function given. If f(x) = x^{2} - c, and f(-2) = 6, then plug in -2 for x in the function: f(-2) = (-2)^{2} - c. Solve and replace f(-2) with 6: 6 = 4 - c; 2 = -c; and c = -2. If you picked (A), you forgot that (-2)^{2} is positive 4.