Hi:
I want count the number of heterozygous individuals.
for autosomes:
I use (AN/2 - nhomalt)
as the heterozygous individuals. Is it correct ?
for X :
I use (AN_female/2 - nhomalt_female)
as the female heterozygous individuals, as for male , I think AN = nhomalt + AC
. so AC = male heterozygous individuals
. but the data tell me it's wrong.
I don't know how to count the number of heterozygous individuals....maybe there's something wrong with my thinking....pls help me...
Thanks in advance!
Thanks for your answer.
But i wander that what's the diffence between the
(AN/2 - nhomalt)
andAC - (2 x nhomalt)
.I think they are the same answer.
But obviously, the results are different
I think it is because
nhomalt
is the number of individuals homozygous for the alternate allele.AN/2
= total number of individuals, but that includes individuals homozygous for the reference allele, heterozygotes, and individuals homozygous for the alternate allele (nhomalt
). So,AN/2 - nhomalt = heterozygotes + reference homozygotes
, not only the number of heterozygotes.