ColSideColors' must be a character vector of length ncol(x)
1
1
Entering edit mode
3.2 years ago
Jakpa ▴ 50

Hello all,

I tried to generate a heatmap using heatmap.2. The following code was used:

heatmap.2(
  as.matrix(sample_dist),
  key=F,
  trace="none",
  Colv = c("cancer", "normal"),
  Rowv ="Colv",
  dendrogram= "none",
  col=colorpanel(100, "black", "white"),
  ColSideColors=myColors[condn],
  RowSideColors=myColors[condn],
  margin=c(10, 10),
  main="Sample Distance Matrix")

Then, I got this error:

Error in heatmap.2(as.matrix(sample_dist), key = F, trace = "none", Colv = c("cancer", : 'ColSideColors' must be a character vector of length ncol(x)

Does this mean that myColors is not same as condn?

This was how I defined myColors and condn

myColors<- brewer.pal(8, "Set3")[1:length(unique(group))]
condn<- factor(c(rep("normal",3), rep("cancer",3)))

Where am I getting it wrong?

Regards,
Anthony

R heatmap.2 differential-gene-expression • 7.0k views
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1
Entering edit mode
3.2 years ago

It is likely that, when you solve this first error, a subsequent error will appear relating to RowSideColors.

The only thing that you need to pass to ColSideColors and RowSideColors are character vectors of colours that have the same length as ncol(x) and nrow(x), respectively.

  • What, currently, is contained in myColours?
  • What is group?
  • What are you aiming to do with this: myColors[condn]?

At the very fundamental level, we can assign a pre-defined colour palette like this:

samples <- c('Primary','Primary','Normal','Met','Normal','Normal','Met','Met','Primary','Normal')
samples <- factor(samples, levels = c('Normal', 'Primary', 'Met'))
RColorBrewer::brewer.pal(11, 'Spectral')[samples]
 [1] "#D53E4F" "#D53E4F" "#9E0142" "#F46D43" "#9E0142" "#9E0142" "#F46D43" "#F46D43" "#D53E4F" "#9E0142"

Other ways to assign colours to factors:

colorRampPalette(c('pink', 'purple', 'red4'))(length(unique(samples)))[samples]
 [1] "#A020F0" "#A020F0" "#FFC0CB" "#8B0000" "#FFC0CB" "#FFC0CB" "#8B0000" "#8B0000" "#A020F0"
[10] "#FFC0CB"

...or even just:

c('pink', 'purple', 'red4')[samples]
 [1] "purple" "purple" "pink"   "red4"   "pink"   "pink"   "red4"   "red4"   "purple" "pink"

Gracias!

Kevin

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0
Entering edit mode

Hi Kevin,

Thank you for your response.

This is what is in myColors:

 [1] "#8DD3C7" "#FFFFB3"

For group I have this:

factor  w/2 levels "HBR; "UHR" : 1 1 1 2 2 2>`

condn:

factor w/2 levels "cancer", "normal" : 2 2 2 1 1 1

The group and condn are what am using for my comparison in my Differential gene Expression. From your examples, I think I have few numbers of colors compare to what i have in group and condn. How do I make this up?

Am relatively new with R

Thank you,
Anthony

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0
Entering edit mode

Can you try to re-format your post? - thanks!

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0
Entering edit mode

Hello Kevin,

I hope the re-formatted post is ok. I am still learning learning how to write code on this platform.

Regards

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0
Entering edit mode

You have 2 colours and 2 groups? If that is the case, then this should work

myColors[condn]

...or:

myColors[group]

For RowSideColors, it is a different problem - I recommend that you avoid using that, for now.

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1
Entering edit mode

Hi Kevin,

I saw the error. It was from sample_dist

I transposed the matrix like this:

sample_dist<- as.matrix(dist(t(assay(rlog_Trans))))

The heatMap is ok now with both groups

Thanks

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0
Entering edit mode

Hello Kelvin, pardon my formatting style. I am still learning it

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