User: John S.
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- 1 year, 8 months ago
Posts by John S.
... I just realized my mistake. I was dividing values that were log transformed, thus, I should have done a subtraction instead. By doing so, I have the same results that limma does. Meaning that here the logFC is directly the difference between the groups rather the ratio (since the values are log tran ...
... Hi guys, I have a doubt regarding the logFC calculation in limma. I searched for the answer in Biostars but I have not found anything that help me to understand my doubt. Supposedly logFC is: LOG2(mean (Group A) / mean (GroupB)) Meaning that if a gene logFC has an expression of 50 in Group A and 10 ...
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