Question: p-value with chi-square test
0
gravatar for Biologist
7 months ago by
Biologist150
Biologist150 wrote:

From this Research paper Table1 Association of RAD51-AS1 expression with clinicopathological features of EOC patients I see that p-value is calculated based on Chi-square test.

 Age   Low-RAD51-AS1  High-RAD51-AS1 P-value
 <50    25 (38.5)      17 (26.6)       0.149
 ≥50    40 (61.5)      47 (73.4)

For the Variable Age the p-value is 0.149

But when I calculated it gave a different value.

data <- data.frame(x= c(25, 40), y=c(17, 47))
chisq.test(data, correct = T)

    Pearson's Chi-squared test with Yates' continuity
    correction

data:  data
X-squared = 1.5728, df = 1, p-value = 0.2098

It is not only with Age even the rest all variable data also gives different p-values compared with the p-values in the Research paper.

What could be the reason for this different p-values? Did I do anything wrong?

ADD COMMENTlink modified 7 months ago by Kevin Blighe39k • written 7 months ago by Biologist150
1
gravatar for Kevin Blighe
7 months ago by
Kevin Blighe39k
Republic of Ireland
Kevin Blighe39k wrote:

Just switch off the continuity correction.

chisq.test(df[,c("High", "Low")], correct=FALSE)

    Pearson's Chi-squared test

data:  df[,c("High", "Low")]
X-squared = 2.0794, df = 1, p-value = 0.1493

Kevin

ADD COMMENTlink written 7 months ago by Kevin Blighe39k

Thank you Kevin. I would also like to know Is it wrong calculation if correct=TRUE. At what times it should be TRUE?

ADD REPLYlink written 7 months ago by Biologist150
1

My background is not pure statistics - it's biology and computer science. That said, bioinformatics overlaps into statistics and many bioinformaticians understand much statistical methodologies, myself included.

Whilst I cannot give a complete definition of continuity correction, I am aware that it is used for slightly similar reasons as performing P value adjustment in expression studies, that is, to prevent overestimation of the statistical significance. When we conduct Pearson Chi-squared test, the assumption is that the frequencies in our contingency table follow a binomial distribution, which is not often true. The continuity correction attempts to 'adjust' for this situation.

If you want to delve further into it, I suggest posting on StackExchange.

ADD REPLYlink written 7 months ago by Kevin Blighe39k
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