Opposite genotype filtering in multisample vcf for 2 population

Question: Opposite genotype filtering in multisample vcf for 2 population

4.9 years ago by

United Kingdom

ck791234 • 0 wrote:

Hi,

I'm trying to filter for opposite genotype from multisample vcf (8 samples) which consist of 2 population (4 samples/population) while maintain the vcf format.

What i want to achieved are as follow:

1. Filter for same genotype in all sample in Population A while genotype in Population B are totally different than Population A.

example: 1/1 in all sample in Population A (s1-s4), none 1/1 in Population B (a1-a4) (genotype in Population B can be a mixture of 0/0 and 0/1).

#desire genotype output

s1 s2 s3 s4 a1 a2 a3 a4

1/1 1/1 1/1 1/1 0/0 0/0 0/0 0/0

1/1 1/1 1/1 1/1 0/0 0/0 0/0 0/1

and so on..

2. Flip the genotype filtering as in (1) where genotype in Population B are same while genotype in Population A is not same as Population B.

#desire genotype output

s1 s2 s3 s4 a1 a2 a3 a4

0/0 0/0 0/0 0/0 1/1 1/1 1/1 1/1

0/0 0/0 0/0 0/1 1/1 1/1 1/1 1/1

and so on..

I tried with SnpSift, however the filter missed 26 combination when involve 1/1 genotype.

The command i used as follow:

cat sample.vcf | java -Xmx4g -jar SnpSift.jar filter "(((countHom()>3)&(countHom()<5))|(countHet()=4)|(countRef()=4)) &((isRef(GEN[0]) & isRef(GEN[1]) & isRef(GEN[2]) & isRef(GEN[3]))|(isHom(GEN[0]) & isVariant(GEN[0]) & isHom(GEN[1])& isVariant(GEN[1]) & isHom(GEN[2]) & isVariant(GEN[2])& isHom(GEN[3]) & isVariant(GEN[3])) | (isHet(GEN[0]) & isHet(GEN[1]) & isHet(GEN[2]) & isHet(GEN[3]))| (isRef(GEN[4]) & isRef(GEN[5]) & isRef(GEN[6]) & isRef(GEN[7]))|(isHom(GEN[4]) & isVariant(GEN[4]) & isHom(GEN[5])& isVariant(GEN[5]) & isHom(GEN[6]) & isVariant(GEN[6])& isHom(GEN[7]) & isVariant(GEN[7])) | (isHet(GEN[4]) & isHet(GEN[5]) & isHet(GEN[6]) & isHet(GEN[7])))"

Does anyone has experience in this filtering? I appreciate any help/advise.

Many thanks

snp genotype snpsift vcf • 1.6k views

ADD COMMENT • link •

modified 4.9 years ago • written 4.9 years ago by ck791234 • 0

Thanks for all the helps & advise.

Script for the opposite filtering with https://github.com/lindenb/jvarkit/wiki/VCFFilterJS:

function accept(v)
    {
    var pop1=["s1","s2","s3","s4"];
    var pop2=["a1","a2","a3","a4"];
    var i;
    var g1 = v.getGenotype(pop1[0]);
    var g2 = v.getGenotype(pop2[0]);
    var g1issame = 1;

    if( !g1.isCalled() ) return false;
    if( !g2.isCalled() ) return false;

    for(i=1;i < pop1.length; ++i)
        {
        if( ! g1.sameGenotype( v.getGenotype(pop1[i]) ) ) g1issame = 0;
        }

    if( g1issame == 1 )
        {
        for(i=0;i < pop2.length; ++i)
            {
            if( g1.sameGenotype( v.getGenotype(pop2[i]) ) ) return false;
            }
        }
    else
        {
        for(i=1;i < pop2.length;++i)
            {
            if( ! g2.sameGenotype( v.getGenotype(pop2[i]) ) ) return false;
            }
        for(i=0;i< pop1.length; ++i)
            {
            if( g2.sameGenotype( v.getGenotype(pop1[i]) ) ) return false;
            }
        }

    return true;
    }
accept(variant);

ADD REPLY • link modified 11 months ago by _r_am ♦ 31k • written 4.9 years ago by ck791234 • 0

4.9 years ago by

Pierre Lindenbaum ♦ 131k

France/Nantes/Institut du Thorax - INSERM UMR1087

Pierre Lindenbaum ♦ 131k wrote:

using my tool https://github.com/lindenb/jvarkit/wiki/VCFFilterJS and the following script:

function accept(v)
    {
    var pop1=["sample1","sample2","sample3"];
    var pop2=["sample4","sample5"];
    var i,j;
    var g1 = v.getGenotype(pop1[0]);
    var g2 = v.getGenotype(pop2[0]);

    if( !g1.isCalled() ) return false;
    if( !g2.isCalled() ) return false;
    if( g1.sameGenotype(g2) ) return false;

    for(i=1;i < pop1.length;++i)
        {
        if( ! g1.sameGenotype( v.getGenotype(pop1[i]) ) ) return false;
        }
    for(i=1;i < pop2.length;++i)
        {
        if( ! g2.sameGenotype( v.getGenotype(pop2[i]) ) ) return false;
        }
    return true;
    }

accept(variant);

you can then reformat the resulting vcf using my tool bioalcidae https://github.com/lindenb/jvarkit/wiki/BioAlcidae

ADD COMMENT • link modified 11 months ago by _r_am ♦ 31k • written 4.9 years ago by Pierre Lindenbaum ♦ 131k

Hi Pierre,

Thanks for the help.

The script still missed condition where 2 opposite genotype are in Population B(a1-a4) and vice versa like as exampled as below which I'm interested to keep (even after I set pop1=["s1","s2","s3","s4"]; pop2=["a1","a2","a3","a4"]):

s1      s2     s3    s4     a1    a2     a3     a4 
1/1    1/1    1/1    1/1    0/0    0/0    0/0    0/1
1/1    1/1    1/1    1/1    0/0    0/1    0/0    0/1

and so on..

Also, what is the j refer to in the script (var i,j)?

ADD REPLY • link modified 11 months ago by _r_am ♦ 31k • written 4.9 years ago by ck791234 • 0

The script still missed condition where 2 opposite genotype

oh I see, It would be something like

function accept(v)
    {
    var pop1=["sample1","sample2","sample3"];
    var pop2=["sample4","sample5"];
    var i;
    var g1 = v.getGenotype(pop1[0]);

    if( !g1.isCalled() ) return false;

    for(i=1;i < pop1.length;++i)
        {
        if( ! g1.sameGenotype( v.getGenotype(pop1[i]) ) ) return false;
        }
    for(i=0;i < pop2.length;++i)
        {
        if( g1.sameGenotype( v.getGenotype(pop2[i]) ) ) return false;
        }
    return true;
    }

accept(variant);

ADD REPLY • link modified 11 months ago by _r_am ♦ 31k • written 4.9 years ago by Pierre Lindenbaum ♦ 131k

The script worked brilliantly to filter for fix genotype in 1 population (eg. 0/0) and opposite mix genotype (0/1 or 1/1 and mix of 0/1 & 1/1) in other population.

My ultimate aim is to have script that will output following within single script :

s1      s2     s3    s4     a1    a2     a3     a4 
1/1    1/1    1/1    1/1    0/0    0/0    0/0    0/1
1/1    1/1    1/1    1/1    0/1    0/0    0/0    0/1
0/0    0/0    0/0    0/1     1/1    1/1    1/1    1/1
0/0    0/1    0/0    0/1     1/1    1/1    1/1    1/1
0/1    0/1    0/1    0/1     1/1    1/1    1/1    0/0
1/1    1/1    1/1    0/0      0/1    0/1    0/1    0/1

and so on ..

I've tried to modified the script but failed. Can you advise?

Thanks

ADD REPLY • link modified 11 months ago by _r_am ♦ 31k • written 4.9 years ago by ck791234 • 0

j is unused. you can remove it.

ADD REPLY • link written 4.9 years ago by Pierre Lindenbaum ♦ 131k

4.9 years ago by

DG ♦ 7.2k

DG ♦ 7.2k wrote:

Have you checked out GEMINI? It does a little more than you you want in that it also adds all sorts of annotations to your dataset as well, but it stores the VCFs (and can include a PED file) in an SQLite database. It has some built in search tools where I think you could set up the right queries to get what you want. Since you can separate your populations as defined groups or cohorts in the database.

ADD COMMENT • link modified 11 months ago by _r_am ♦ 31k • written 4.9 years ago by DG ♦ 7.2k

Thanks Dan for the info,

I work with non-human and GEMINI is only for human.

ADD REPLY • link written 4.9 years ago by ck791234 • 0

No problem, there may be a way to "hack" it to work since you aren't really interested in the annotations anyway, just the genotype storage and selection. But it may be easier to take another approach.

ADD REPLY • link written 4.9 years ago by DG ♦ 7.2k

4.9 years ago by

DG ♦ 7.2k

DG ♦ 7.2k wrote:

Looking around I think the tool you probably want to use is vcf-contrast from the VCFtools tool set. It is specifically designed for looking for differences between groups in this manner.

ADD COMMENT • link modified 11 months ago by _r_am ♦ 31k • written 4.9 years ago by DG ♦ 7.2k

vcf-constrast still missed condition where 2 opposite genotype are present in Pop.B and vice versa as following:

s1      s2     s3    s4     a1    a2     a3     a4 
1/1    1/1    1/1    1/1    0/0    0/0    0/0    0/1

ADD REPLY • link modified 11 months ago by _r_am ♦ 31k • written 4.9 years ago by ck791234 • 0

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